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4.9x^2-2.4x-1.4=0
a = 4.9; b = -2.4; c = -1.4;
Δ = b2-4ac
Δ = -2.42-4·4.9·(-1.4)
Δ = 33.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{33.2}}{2*4.9}=\frac{2.4-\sqrt{33.2}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{33.2}}{2*4.9}=\frac{2.4+\sqrt{33.2}}{9.8} $
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